A string within single quote marks, in the format of 'YYYY-MM-DD[*HH:MI[:SS]]', where * can be a colon (:) or a blank space, or the. 5 days to a given date. Examples of Results in Months. The idea is to find how many years, months, and days they have served there. SYSDATE) and subtracting a date from a timestamp (e. 0. 4193548. 10 months ago by below86. I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. MONTHS_BETWEEN = 1. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. Example 2. In this, we will add the number of years that we expect this person to turn in a given year, based on the DATEDIFF( ) results. And you can use intervals, but using month intervals for. DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. montant / (datediff (NEW. DATE_FORMAT () Format date as specified. . If you omit it, the ROUND () function. Answer: You can use the months_between function and convert it easily yo years between and decades between two dates: months_between/12 = years between. This previous question indicates that there is a date format in Oracle that would make your year 92 into 2092 (i. The following illustrates the syntax of the DATEPART. You could also use the add_months function: AND s. SQL was invented in the 1970s by IBM Computer Scientists. The system calculates the number of complete months between given dates. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. ArrivalDate, Trips. Sorted by: 10. So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. 3. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. DATEDIFF accepts either. e. The dates do not have to be in the same format in the extract file, but the format of each must be supported. The DATEDIFF SQL Server function allows to calculate the difference between two values of date and time in units of a certain element (i. Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. 264k 58 58 gold badges 366 366 silver badges 409 409 bronze badges. getMonth (); int m2 = date2. date_open END. (Oct 10, 2006 - June 14, 2005 = 69) In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input. The part to return. id = a. Just divide the total by 7 to get the weeks and then calculate the remaining days. create or replace FUNCTION DATEDIFF ( P_TYPE_DATE IN VARCHAR2 , P_START_DATE IN TIMESTAMP , P_END_DATE IN TIMESTAMP ) RETURN NUMBER AS v_Result NUMBER := -1; BEGIN IF. Return the current time. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. lastModified - w. DATEADD () Adds or subtracts a specified time interval from a specified date. dbeaver. 2. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. 1. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. TIMESTAMP Functions. Oracle/PLSQL: MONTHS_BETWEEN Function 2. 14977 Days 7 Hours 36 Minutes 56 Seconds. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. 2. 99. dividing by 365. Extract a value of a date time field e. datediff (q,start date,end date) i. Modified 5 years, 9 months ago. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also considered one month. Here's an example. then the following should be the result. DATEDIFF Examples Using All Options. I want to calculate the difference between two dates in OBIEE10g in Year/Months/Days format similar to the output of below SQL. You need to add 1 to the DATEDIFF function and it will work as you want. As another option you could use the months_between () function, and manipulate the value that gives you into the three parts. Enter a date format string that describes the Date2 parameter. The number is the number of seconds elapsed since midnight, January 1, 1970. For each employee hired before 1992, display the employee’s last name, hire date and calculate the number of YEARS between TODAY and the date the employee was hired. In case the full DDL for the database is requested, I can provide it (although it will probably exceed the character limit of Stackexchange). 1. user637544 Jun 1 2009 — edited Jun 1 2009. Here are the 10 federal holidays a year, almost one per month: New Year’s Day on January 1; Martin Luther King’s Birthday on the. SELECT TIMESTAMPDIFF (MONTH, '2012-05-05', '2012-06-04') -- Outputs. In SQL Server here's a little trick to do that: SELECT CAST(FLOOR(CAST(CURRENT_TIMESTAMP AS float)) AS DATETIME) You cast the DateTime into a float, which represents the Date as the integer portion and the Time as the fraction of a day that's passed. SELECT datediff ( TIMESTAMP '1981-04-01 10:11:13', TIMESTAMP '2022-04-03 17:48:09') as diff FROM DUAL; Outputs: DIFF. What this allows you to do is pass in two TIMESTAMP or DATETIME values (or even DATE as MySQL will auto-convert) as well as the unit of time you want to base your difference on. Note that the syntax for datediff () uses the SQL Server version of the function. 1. g. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. ReturnDate) AS nvarchar(max)) END) AS [Duration] As a side note: I used nvarchar(max) for consistency with the first part of your query. Here is some T-SQL that gives you the number of years, months, and days since the day specified in @date. 0208 days. 1 - Find the total months count till today's date using DATEDIFF function -. Month-difference between any given two dates: I'm surprised this hasn't been mentioned yet: Have a look at the TIMESTAMPDIFF() function in MySQL. Asked 8 years, 2 months ago. MONTHS_BETWEEN: Returns an estimate of the number of months between expression1 and expression2. In Oracle, You can use the MONTHS_BETWEEN function with TRUNC and MOD function as follows: SQL> SELECT 2 TRUNC(TRUNC(MONTHS_BETWEEN(SYSDATE, DATE '2014-08. It counts the number of year boundaries between two dates. subtract and give the difference in number of months. SQL Retrieve the records of previous month. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. DateDiff is not a function that exists in Oracle. Currently, my code just returns zero on the right side of the decimal place. The application passes in two parameters: a string representing the number of the desired month (i. datediff isn't a function in Oracle. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. 997268. USE MASTER GO -. All I need is to find the diff of these kind of dates in. first weeks into oracle. If they are identical down to the second then, presumably, returning 0 is the right answer. The return type is always DATE, regardless of the datatype of date. 2. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. I have a creation date column in the table. SELECT select AVG (months_between (SYSDATE,DOB)/12) AS AVERAGE_AGE_IN_YEARS. Sorted by: 55. Since the value does not equal an entire month the result is 0. Kilian Hekhuis. The screenshot below shows the data I want as well as the incorrect month between results I am obtaining. So, i need to unite them to one column to check if the time difference is lower the 5. For example the difference between 1st March 2011 and 3rd March 2012 is 1. ----- we travel not to escape life but for life not to escape us. Phil The current month (last date in db so in spetember we get results for august) Aug will be represented by MAX[Date] I neet the total for AUG, July, June so im trying to get the aggregate sales for the last 3 months as one number select max ([retailsales. Click Add Step to convert your column to a DateTime field. This can have results that you are not expecting. g. proc sql noprint; create table daystoOverdue_list as select distinct business_object_rk , DateDiff (DAY, value_dt, Today ()) as value_dt from case_DataTable_d as tbl where tbl. Difference of two dates in months user637544 Jun 1 2009 — edited Jun 1 2009 i need to find the difference of two dates as the number of months: find the last day. Then type a formula like one of the following. 0 is for 1/1/1900, and getdate is the current date --(i used a set date bc dates will change as this post gets older). If the dates are really timestamps, then this is easy - subtract them and the result is a day to second interval. You have to cast it first, using to_date: select to_date ('2000-01-01', 'yyyy-MM-dd') - to_date ('2000-01-02', 'yyyy-MM-dd'). The second parameter defaults to the current date. As you can see it means that year should be -1, and month 0. DP_MONTHは、入力日付をキャプチャする月の間隔を返します。(2006年10月- 2005年6月= 16)CONCAT((DATEDIFF(Minute,StartDate,EndDate)/60),':', (DATEDIFF(Minute,StartDate,EndDate)%60)) TimeTaken , and instead of calculating time difference once again using datediff if I can use the time taken value column which is already calculated the query execution will be faster. Note that it is subtracting the second from the first, so you must have them in this order. . How to calculate days difference between two dates without leap year (365 days each year)? Thank you so much! I am new to Oracle Community Support, and I assumed that if I posted question in Oracle under SQL and PL/SQL, people would understand what I need. The name of the order date month is printed, followed by the day of the month, a comma, and four-digit year. Dates are always a joy to work with in any programming language, SQL not excluded. 5 days to a given date. NEW_TIME returns the date and time in time zone timezone2 when date and time in time zone timezone1 are date. 7. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. user637544 Jun 1 2009 — edited Jun 1 2009. date_from, evnt. 9. What is elapsed time in DB? DB Time is the Oracle server process CPU consumption and all non-idle wait time. July 16, 2013 at 3:32 pm. EXTRACT the number of years from the interval. We would like to show you a description here but the site won’t allow us. row_number () over (partition by serialid, dateadd (dd,0, datediff (dd,0,dateadd (HH,8,createddatetime))) order by createddatetime desc) rnk. If you omit fmt, then date is rounded to the. WHERE -- >= 2016-02-01 00:00:00. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. 365 days elapse between the two dates. date. For years, just do months_between/12. How can I find the difference between two date columns in Oracle? Answer: Oracle supports date arithmetic and you can make expressions like "date1 – date2" using date subtraction to get the difference between the two dates. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. 2. SELECT DATEADD ( year, DATEDIFF ( year, 0, GETDATE ()), 0 ) 這個 SQL 的技巧是先取得和 1900-01-01 - 也就是上面的 0 的意思,SQL Server 中的第零天 - 差幾年 (從 DATEDIFF 得到一個整數),再用 DATEADD 加 0 來將整數再轉成日期的型態。. If date1 is later than date2, then the result is positive. Current Date/Time. DECLARE @date datetime2 = '2021-01-07 14:36:17. The syntax for the DATEDIFF function in SQL Server (Transact-SQL) is: DATEDIFF( interval, date1, date2 ) Parameters or Arguments interval. This question was incorrectly asked. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. DP_MONTH returns the distance between the months capturing the input dates. You could, of course, write your own function and call that. 6. Example 29 : Get number of seconds left today (till 23:59:59 hr. Arguments. The fact that the function returns an integer number of months both when the days of the month are the same (e. PROJECTED_COMPLETION,. floor(months_between(sysdate, dateofbirth)/12) But, months_between function treats end of month day specially. You need to use DATEADD - not DATEDIFF. The system always returns a positive number regardless of. DATEENTERED between dateadd (mm, datediff (mm, 0, dateadd (MM, -1, getdate ())), 0) and dateadd (ms, -3, dateadd (mm,. Returns a date string or the current date. (i. Oracle datediff function. The date functions are summarized in the table below. The format argument is a string format that specifies which unit the date should be rounded to. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. It can be one of. create or replace function FUN_DATEDIFF ( dateFrom in date, dateTo in date, interval in char return number AS result number; beginThe default is zero (0). Do this even for a single day—e. Table 9. For example when I place 01/01/04 as the. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. The first one involves getting the difference in days and then converting it to 'x year y month z days'. I know it exists in SQL Server. e. mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future. %DateAdd . These are already in hour:minute:second format! with rws as ( select timestamp'2017-03-01 01:00:00' t1, timestamp'2017-03-01 02:34:56' t2 from dual ) select t2-t1 diff_interval from rws; DIFF_INTERVAL +00 01:34:56. If the days of the month are both the last day of the month (e. So to calculate the number of day from a date to the end of the month you could write. Again, the expected results would be a value of 1. Oracle offers its own solution, although does not have the DATEDIFF function. Also, you need to put your dates into single quotes: use '2-2-2011' instead of simply 2-2-2011. 25) This seems to be another common approach - and was also given in a comment on my question. 3. 1. To get the months or years separately, use extract. get the previous last date of the month in oracle sql. 2) format. sql. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. Share. This field level rule lets you display the difference between two dates. However, The problem is different number of records because DATEDIFF(month,a,b)<=4 in SQL Server returns only the month difference whereas months_between(a,b)<=4 in oracle returns the. For example, with some sample dates: select months_between (date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ---------- 38. 7 months ago. DOW: returns the day of the week, between Sunday (0) and Saturday (6) DOY: returns the day of the year. The solution takes as base the first known date by SQL Server (1900-01-01). Then it calculates the number of months that have passed until your given date (@test) by fours steps: 1. 0 months apart:Asked 3 years, 4 months ago. DATE_ADD () Add time values (intervals) to a date value. Can Any one help me please. So I'm guessing it is an available function for mysql, but not for oracle databases. SELECT select AVG (months_between (SYSDATE,DOB)) AS AVERAGE_AGE_IN_MONTHS. months_between/120 = decades_between. ) and the. date or field. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Thank you. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. You can substitute the parameters used as an example for the values in your query. 5. When the reporting date month is the same as the target month you can get a round up Here is a PostgreSQL function with the exact same behavior as the Oracle MONTHS_BETWEEN function. Hot Network Questions Murder mystery, probably by Asimov, but SF plays a. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. HEH! One big difference you’ll find is that adding or subtracting two date values in Oracle leaves you with a number, not a date. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. Stack Overflow. For formatting functions, refer to Section 9. Asked 10 years, 2 months ago. Outputs the fraction of days between two dates: DIFFERENCE ---------- 1. To get the number of months you could use months_between. 0. maybe something like passing an "m" as one of the parameters. However, The. 2188940092 Example 2 Date 1: 10th March 2011 Date 2: 1st Feb 2011 MONTHS_BETWEEN = 1. To create the rows, use the month generation technique above. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. 365 days elapse between the two dates. I had a problem with a date query using the operator 'between'. For the last row return the calculated date. fin,NEW. Viewed 14k times 2 I'm looking to get total number of days including the Start Date and End Date, some examples below:. Description It's easy to do date arithmetic in Oracle Database, but it can be hard to remember the formulas. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. If this query is executed between December 26 and December 31, you'll still. FROM HR. Step-7: SQL Query to Calculate the Number of Months between two specific dates : Now let’s find the number of months between the dates of an order of ‘Maserati’ and ‘Ferrari’ in the table. Oracle SQL Hours Difference between dates in HH:MM:SS. should work fine. Currently, my code just returns zero on the right side of the decimal place. 1. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. . created_date - adhh. 2. HQL And datediff() Functions. The DateDiff function returns how many seconds, months, years - whatever interval you specify between the first date (here 0) and the second date (here the current date). Computes the number of months between <date_1> and <date_2>. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. Follow answered Oct 5, 2009 at 15:32. I am having issues with DATE functions in SQL Plus. Then it would also be helpful to be able to remove holidays from this. SELECT DATEADD(month, DATEDIFF(month, 0, @mydate), 0) AS StartOfMonth Share. Viewed 516 times 0 Everyone, the table relationship diagram for the database is the below one. Q&A for work. cust_field_nm eq "x_case_dte_dd" and datepart. Before using this function, you must set the NLS_DATE_FORMAT parameter to display 24-hour time. There are many tricks to generate rows in Oracle Database. There are similar questions on the site; however as I could see, none of them asks for an output as. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. DatePart. Modified 9 years ago. CODE = 'CONTACT_CLIENT' THEN a. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. SS: 差異を秒数で計算します。. The difference in hours, minutes or seconds can be found by multiplying this number by 24, 24*60 or 24*60*60 respectively. For example: print &order_date () edit 'Month dd, YYYY'. sql. Oracle GoldenGate add trandata errors. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. Which leads me to believe that it is treating February. AT TIME ZONE. When you subtract two dates in Oracle, you get the number of days between the two values. *Subtract the two date values, divide by (60 seconds * 60 minutes *. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified start date and end date. One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. Two dates to calculate the number of days between. Let’s factor it in! First, we will take the person’s birthday and will use the DATEADD( ) function. The first one involves getting the difference in days and then converting it to 'x year y month z days'. Add a number of months (n) to a date and return the same day which is n of months away. TIMESTAMPDIFF ( numeric-expression string-expression. Étienne Miret. For example, adding three months or 12 days to a starting date. Adds days, months, and years to the date and returns the result. date_to) - (DATEDIFF(WK, evnt. subtracting date literals as pure dates without conversion. The second method uses an extract function to obtain the years, months, and days separately. How to generate days, weeks, or months between two dates in Oracle Database June 1, 2021 | 25 minute read Chris Saxon Developer Advocate There are. I have two Oracle columns (in a VIEW, not a table) - DateOfBirth and MembershipDate. I believe you want: Select id, datediff (day, min (hire) max (hire)) as Difference From Employees group by id having count (terminated) < count (*) -- at least one NULL value. In this article, we take an existing date and the current date and using the "GetDate" function to find the years, months and days. ) Solution 1: You can use this provided your date is in the DB datetime format Solution 2: Or Solution: You do not need to use a row generator to enumerate every day to get the number of week days - it can be done using a simple calculation: From my answer here: Difference of two DATE datatype values in Oracle represents number of days between them so. I put a few more examples into a table and got the following results. User-1629274867 posted Hi, I have replaced MS Oracle Client with OPD. 65. It shows the INTER CTE. date_open are both of type date, you can simply subtract them to get a difference in days. g. SELECT DATEDIFF(day,'2008-06-05','2008-08-05') AS DiffDate from dual is not working in SQL ERROR : ORA-00904: "DATEDIFF": invalid identifier 00904. You may need to change date format to match the a given date format and verify that 31 day months work for your specific scenarios. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). Select * from table where date is between '01-JAN-02' and '17-JAN-02'. Finding the seconds difference can be done as follows: SELECT (mod_date_time - create_date_time) * 24 * 60 * 60 as "seconds_diff" FROM t1. But since it's a finite set, you can just get. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. 9. I didn’t know you answered questions including MySQL and. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. 32. (date1 - date2)It should return 1 but as they consider it as a number so they return 70 instead of 1. DATEDIFF (datepart, startdate, enddate) which can return the difference in years, months, days etc. And then we need to convert the output of DATEPART to a 2-digit month number. Voila! You've the the last day of the month containing your reference point in time. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. 25) This seems to be another common approach - and was also given in a comment on my question. event_id, evnt. The two date fields are "timestamp" format (date and time). If you want the "exact" (as far as floating point gets) average, use. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. · User1416329745 posted ANSI SQL 1992. DATEDIFF. Step 5: Change Sort column. ExampleHere I need to calculate the difference of the two dates in the PostgreSQL. You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365. 0 and later: Fusion OTBI Analysis - How to Convert Date of Birth to Age. So, Feb-28 to Mar-28 is a month. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: SQL> with 2 test (start_date, end_date) as 3 (select date '2020-10-01', 4 date '2020-11-02' 5 from dual 6 ), 7 calendar as 8 (select start_date + level - 1 datum 9 from test 10 connect by level <= end_date - start_date + 1 11 ) 12 select to_char(datum, 'yyyy. Get the number of months between two dates. You have the option to change the data type there. 2 Answers Sorted by: 7 Why do you believe that it is not a good idea to subtract two dates to get the number of days between them? That's certainly the. When a user enters JAN 2009 - I want the worksheet to show data from Jan, Feb, Mar, Apr, May and June (2009). MonthDiff = DateDiff ("m", startdate, enddate) End If. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. Example 3: Comparing dates for elapsed time (in months) since a given date: Using the DATEDIFF function, we can calculate the elapsed time in months from a specific date until the current date. date_open are both of type date, you can simply subtract them to get a difference in days. In SQL, we can add or subtract days, months, or years to a date by using the DATEADD function. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. 2425. The SQL DATEDIFF() function is an in-built function in SQL that is used to return the difference (as a signed integer value) between two dates or times.